Divide using synthetic division $$ ( x^{4}-3x^{2}-5x+20 ) \div ( x+5 ) $$
Answer
The synthetic division table is:
$$ \begin{array}{c|rrrrr}-5&1&0&-3&-5&20\\& & -5& 25& -110& \color{black}{575} \\ \hline &\color{blue}{1}&\color{blue}{-5}&\color{blue}{22}&\color{blue}{-115}&\color{orangered}{595} \end{array} $$The solution is:
$$ \frac{ x^{4}-3x^{2}-5x+20 }{ x+5 } = \color{blue}{x^{3}-5x^{2}+22x-115} ~+~ \frac{ \color{red}{ 595 } }{ x+5 } $$Explanation
Step 1 : Write down the coefficients of the dividend into division table. Put the zero from $ x + 5 = 0 $ ( $ x = \color{blue}{ -5 } $ ) at the left.
$$ \begin{array}{c|rrrrr}\color{blue}{-5}&1&0&-3&-5&20\\& & & & & \\ \hline &&&&& \end{array} $$Step 1 : Bring down the leading coefficient to the bottom row.
$$ \begin{array}{c|rrrrr}-5&\color{orangered}{ 1 }&0&-3&-5&20\\& & & & & \\ \hline &\color{orangered}{1}&&&& \end{array} $$Step 2 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ -5 } \cdot \color{blue}{ 1 } = \color{blue}{ -5 } $.
$$ \begin{array}{c|rrrrr}\color{blue}{-5}&1&0&-3&-5&20\\& & \color{blue}{-5} & & & \\ \hline &\color{blue}{1}&&&& \end{array} $$Step 3 : Add down last column: $ \color{orangered}{ 0 } + \color{orangered}{ \left( -5 \right) } = \color{orangered}{ -5 } $
$$ \begin{array}{c|rrrrr}-5&1&\color{orangered}{ 0 }&-3&-5&20\\& & \color{orangered}{-5} & & & \\ \hline &1&\color{orangered}{-5}&&& \end{array} $$Step 4 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ -5 } \cdot \color{blue}{ \left( -5 \right) } = \color{blue}{ 25 } $.
$$ \begin{array}{c|rrrrr}\color{blue}{-5}&1&0&-3&-5&20\\& & -5& \color{blue}{25} & & \\ \hline &1&\color{blue}{-5}&&& \end{array} $$Step 5 : Add down last column: $ \color{orangered}{ -3 } + \color{orangered}{ 25 } = \color{orangered}{ 22 } $
$$ \begin{array}{c|rrrrr}-5&1&0&\color{orangered}{ -3 }&-5&20\\& & -5& \color{orangered}{25} & & \\ \hline &1&-5&\color{orangered}{22}&& \end{array} $$Step 6 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ -5 } \cdot \color{blue}{ 22 } = \color{blue}{ -110 } $.
$$ \begin{array}{c|rrrrr}\color{blue}{-5}&1&0&-3&-5&20\\& & -5& 25& \color{blue}{-110} & \\ \hline &1&-5&\color{blue}{22}&& \end{array} $$Step 7 : Add down last column: $ \color{orangered}{ -5 } + \color{orangered}{ \left( -110 \right) } = \color{orangered}{ -115 } $
$$ \begin{array}{c|rrrrr}-5&1&0&-3&\color{orangered}{ -5 }&20\\& & -5& 25& \color{orangered}{-110} & \\ \hline &1&-5&22&\color{orangered}{-115}& \end{array} $$Step 8 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ -5 } \cdot \color{blue}{ \left( -115 \right) } = \color{blue}{ 575 } $.
$$ \begin{array}{c|rrrrr}\color{blue}{-5}&1&0&-3&-5&20\\& & -5& 25& -110& \color{blue}{575} \\ \hline &1&-5&22&\color{blue}{-115}& \end{array} $$Step 9 : Add down last column: $ \color{orangered}{ 20 } + \color{orangered}{ 575 } = \color{orangered}{ 595 } $
$$ \begin{array}{c|rrrrr}-5&1&0&-3&-5&\color{orangered}{ 20 }\\& & -5& 25& -110& \color{orangered}{575} \\ \hline &\color{blue}{1}&\color{blue}{-5}&\color{blue}{22}&\color{blue}{-115}&\color{orangered}{595} \end{array} $$Bottom line represents the quotient $ \color{blue}{ x^{3}-5x^{2}+22x-115 } $ with a remainder of $ \color{red}{ 595 } $.