The synthetic division table is:
$$ \begin{array}{c|rr}2&20&-96\\& & \color{black}{40} \\ \hline &\color{blue}{20}&\color{orangered}{-56} \end{array} $$The solution is:
$$ \frac{ 20x-96 }{ x-2 } = \color{blue}{20} \color{red}{~-~} \frac{ \color{red}{ 56 } }{ x-2 } $$Step 1 : Write down the coefficients of the dividend into division table. Put the zero from $ x -2 = 0 $ ( $ x = \color{blue}{ 2 } $ ) at the left.
$$ \begin{array}{c|rr}\color{blue}{2}&20&-96\\& & \\ \hline && \end{array} $$Step 1 : Bring down the leading coefficient to the bottom row.
$$ \begin{array}{c|rr}2&\color{orangered}{ 20 }&-96\\& & \\ \hline &\color{orangered}{20}& \end{array} $$Step 2 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ 2 } \cdot \color{blue}{ 20 } = \color{blue}{ 40 } $.
$$ \begin{array}{c|rr}\color{blue}{2}&20&-96\\& & \color{blue}{40} \\ \hline &\color{blue}{20}& \end{array} $$Step 3 : Add down last column: $ \color{orangered}{ -96 } + \color{orangered}{ 40 } = \color{orangered}{ -56 } $
$$ \begin{array}{c|rr}2&20&\color{orangered}{ -96 }\\& & \color{orangered}{40} \\ \hline &\color{blue}{20}&\color{orangered}{-56} \end{array} $$Bottom line represents the quotient $ \color{blue}{ 20 } $ with a remainder of $ \color{red}{ -56 } $.