Divide using synthetic division $$ ( x^{3}+4x^{2}-37x-40 ) \div ( x ) $$
Answer
The synthetic division table is:
$$ \begin{array}{c|rrrr}0&1&4&-37&-40\\& & 0& 0& \color{black}{0} \\ \hline &\color{blue}{1}&\color{blue}{4}&\color{blue}{-37}&\color{orangered}{-40} \end{array} $$The solution is:
$$ \frac{ x^{3}+4x^{2}-37x-40 }{ x } = \color{blue}{x^{2}+4x-37} \color{red}{~-~} \frac{ \color{red}{ 40 } }{ x } $$Explanation
Step 1 : Write down the coefficients of the dividend into division table.Put the zero at the left.
$$ \begin{array}{c|rrrr}\color{blue}{0}&1&4&-37&-40\\& & & & \\ \hline &&&& \end{array} $$Step 1 : Bring down the leading coefficient to the bottom row.
$$ \begin{array}{c|rrrr}0&\color{orangered}{ 1 }&4&-37&-40\\& & & & \\ \hline &\color{orangered}{1}&&& \end{array} $$Step 2 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ 0 } \cdot \color{blue}{ 1 } = \color{blue}{ 0 } $.
$$ \begin{array}{c|rrrr}\color{blue}{0}&1&4&-37&-40\\& & \color{blue}{0} & & \\ \hline &\color{blue}{1}&&& \end{array} $$Step 3 : Add down last column: $ \color{orangered}{ 4 } + \color{orangered}{ 0 } = \color{orangered}{ 4 } $
$$ \begin{array}{c|rrrr}0&1&\color{orangered}{ 4 }&-37&-40\\& & \color{orangered}{0} & & \\ \hline &1&\color{orangered}{4}&& \end{array} $$Step 4 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ 0 } \cdot \color{blue}{ 4 } = \color{blue}{ 0 } $.
$$ \begin{array}{c|rrrr}\color{blue}{0}&1&4&-37&-40\\& & 0& \color{blue}{0} & \\ \hline &1&\color{blue}{4}&& \end{array} $$Step 5 : Add down last column: $ \color{orangered}{ -37 } + \color{orangered}{ 0 } = \color{orangered}{ -37 } $
$$ \begin{array}{c|rrrr}0&1&4&\color{orangered}{ -37 }&-40\\& & 0& \color{orangered}{0} & \\ \hline &1&4&\color{orangered}{-37}& \end{array} $$Step 6 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ 0 } \cdot \color{blue}{ \left( -37 \right) } = \color{blue}{ 0 } $.
$$ \begin{array}{c|rrrr}\color{blue}{0}&1&4&-37&-40\\& & 0& 0& \color{blue}{0} \\ \hline &1&4&\color{blue}{-37}& \end{array} $$Step 7 : Add down last column: $ \color{orangered}{ -40 } + \color{orangered}{ 0 } = \color{orangered}{ -40 } $
$$ \begin{array}{c|rrrr}0&1&4&-37&\color{orangered}{ -40 }\\& & 0& 0& \color{orangered}{0} \\ \hline &\color{blue}{1}&\color{blue}{4}&\color{blue}{-37}&\color{orangered}{-40} \end{array} $$Bottom line represents the quotient $ \color{blue}{ x^{2}+4x-37 } $ with a remainder of $ \color{red}{ -40 } $.