The synthetic division table is:
$$ \begin{array}{c|rrr}-5&1&0&-20\\& & -5& \color{black}{25} \\ \hline &\color{blue}{1}&\color{blue}{-5}&\color{orangered}{5} \end{array} $$The solution is:
$$ \frac{ x^{2}-20 }{ x+5 } = \color{blue}{x-5} ~+~ \frac{ \color{red}{ 5 } }{ x+5 } $$Step 1 : Write down the coefficients of the dividend into division table. Put the zero from $ x + 5 = 0 $ ( $ x = \color{blue}{ -5 } $ ) at the left.
$$ \begin{array}{c|rrr}\color{blue}{-5}&1&0&-20\\& & & \\ \hline &&& \end{array} $$Step 1 : Bring down the leading coefficient to the bottom row.
$$ \begin{array}{c|rrr}-5&\color{orangered}{ 1 }&0&-20\\& & & \\ \hline &\color{orangered}{1}&& \end{array} $$Step 2 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ -5 } \cdot \color{blue}{ 1 } = \color{blue}{ -5 } $.
$$ \begin{array}{c|rrr}\color{blue}{-5}&1&0&-20\\& & \color{blue}{-5} & \\ \hline &\color{blue}{1}&& \end{array} $$Step 3 : Add down last column: $ \color{orangered}{ 0 } + \color{orangered}{ \left( -5 \right) } = \color{orangered}{ -5 } $
$$ \begin{array}{c|rrr}-5&1&\color{orangered}{ 0 }&-20\\& & \color{orangered}{-5} & \\ \hline &1&\color{orangered}{-5}& \end{array} $$Step 4 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ -5 } \cdot \color{blue}{ \left( -5 \right) } = \color{blue}{ 25 } $.
$$ \begin{array}{c|rrr}\color{blue}{-5}&1&0&-20\\& & -5& \color{blue}{25} \\ \hline &1&\color{blue}{-5}& \end{array} $$Step 5 : Add down last column: $ \color{orangered}{ -20 } + \color{orangered}{ 25 } = \color{orangered}{ 5 } $
$$ \begin{array}{c|rrr}-5&1&0&\color{orangered}{ -20 }\\& & -5& \color{orangered}{25} \\ \hline &\color{blue}{1}&\color{blue}{-5}&\color{orangered}{5} \end{array} $$Bottom line represents the quotient $ \color{blue}{ x-5 } $ with a remainder of $ \color{red}{ 5 } $.