Divide using synthetic division $$ ( 6x^{2}+x-2 ) \div ( -2 ) $$
Answer
The synthetic division table is:
$$ \begin{array}{c|rrr}0&6&1&-2\\& & 0& \color{black}{0} \\ \hline &\color{blue}{6}&\color{blue}{1}&\color{orangered}{-2} \end{array} $$The solution is:
$$ \frac{ 6x^{2}+x-2 }{ x } = \color{blue}{6x+1} \color{red}{~-~} \frac{ \color{red}{ 2 } }{ x } $$Explanation
Step 1 : Write down the coefficients of the dividend into division table.Put the zero at the left.
$$ \begin{array}{c|rrr}\color{blue}{0}&6&1&-2\\& & & \\ \hline &&& \end{array} $$Step 1 : Bring down the leading coefficient to the bottom row.
$$ \begin{array}{c|rrr}0&\color{orangered}{ 6 }&1&-2\\& & & \\ \hline &\color{orangered}{6}&& \end{array} $$Step 2 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ 0 } \cdot \color{blue}{ 6 } = \color{blue}{ 0 } $.
$$ \begin{array}{c|rrr}\color{blue}{0}&6&1&-2\\& & \color{blue}{0} & \\ \hline &\color{blue}{6}&& \end{array} $$Step 3 : Add down last column: $ \color{orangered}{ 1 } + \color{orangered}{ 0 } = \color{orangered}{ 1 } $
$$ \begin{array}{c|rrr}0&6&\color{orangered}{ 1 }&-2\\& & \color{orangered}{0} & \\ \hline &6&\color{orangered}{1}& \end{array} $$Step 4 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ 0 } \cdot \color{blue}{ 1 } = \color{blue}{ 0 } $.
$$ \begin{array}{c|rrr}\color{blue}{0}&6&1&-2\\& & 0& \color{blue}{0} \\ \hline &6&\color{blue}{1}& \end{array} $$Step 5 : Add down last column: $ \color{orangered}{ -2 } + \color{orangered}{ 0 } = \color{orangered}{ -2 } $
$$ \begin{array}{c|rrr}0&6&1&\color{orangered}{ -2 }\\& & 0& \color{orangered}{0} \\ \hline &\color{blue}{6}&\color{blue}{1}&\color{orangered}{-2} \end{array} $$Bottom line represents the quotient $ \color{blue}{ 6x+1 } $ with a remainder of $ \color{red}{ -2 } $.