Divide using synthetic division $$ ( 5x ) \div ( -x+3 ) $$

The synthetic division table is:

$$ \begin{array}{c|rr}-3&5&0\\& & \color{black}{-15} \\ \hline &\color{blue}{5}&\color{orangered}{-15} \end{array} $$

The solution is:

$$ \frac{ 5x }{ x+3 } = \color{blue}{5} \color{red}{~-~} \frac{ \color{red}{ 15 } }{ x+3 } $$

Step 1 : Write down the coefficients of the dividend into division table. Put the zero from $ x + 3 = 0 $ ( $ x = \color{blue}{ -3 } $ ) at the left.

$$ \begin{array}{c|rr}\color{blue}{-3}&5&0\\& & \\ \hline && \end{array} $$

Step 1 : Bring down the leading coefficient to the bottom row.

$$ \begin{array}{c|rr}-3&\color{orangered}{ 5 }&0\\& & \\ \hline &\color{orangered}{5}& \end{array} $$

Step 2 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ -3 } \cdot \color{blue}{ 5 } = \color{blue}{ -15 } $.

$$ \begin{array}{c|rr}\color{blue}{-3}&5&0\\& & \color{blue}{-15} \\ \hline &\color{blue}{5}& \end{array} $$

Step 3 : Add down last column: $ \color{orangered}{ 0 } + \color{orangered}{ \left( -15 \right) } = \color{orangered}{ -15 } $

$$ \begin{array}{c|rr}-3&5&\color{orangered}{ 0 }\\& & \color{orangered}{-15} \\ \hline &\color{blue}{5}&\color{orangered}{-15} \end{array} $$

Bottom line represents the quotient $ \color{blue}{ 5 } $ with a remainder of $ \color{red}{ -15 } $.

Synthetic Division Calculator