Divide using synthetic division $$ ( 4x^{2}-3x-1 ) \div ( 1 ) $$
Answer
The synthetic division table is:
$$ \begin{array}{c|rrr}0&4&-3&-1\\& & 0& \color{black}{0} \\ \hline &\color{blue}{4}&\color{blue}{-3}&\color{orangered}{-1} \end{array} $$The solution is:
$$ \frac{ 4x^{2}-3x-1 }{ x } = \color{blue}{4x-3} \color{red}{~-~} \frac{ \color{red}{ 1 } }{ x } $$Explanation
Step 1 : Write down the coefficients of the dividend into division table.Put the zero at the left.
$$ \begin{array}{c|rrr}\color{blue}{0}&4&-3&-1\\& & & \\ \hline &&& \end{array} $$Step 1 : Bring down the leading coefficient to the bottom row.
$$ \begin{array}{c|rrr}0&\color{orangered}{ 4 }&-3&-1\\& & & \\ \hline &\color{orangered}{4}&& \end{array} $$Step 2 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ 0 } \cdot \color{blue}{ 4 } = \color{blue}{ 0 } $.
$$ \begin{array}{c|rrr}\color{blue}{0}&4&-3&-1\\& & \color{blue}{0} & \\ \hline &\color{blue}{4}&& \end{array} $$Step 3 : Add down last column: $ \color{orangered}{ -3 } + \color{orangered}{ 0 } = \color{orangered}{ -3 } $
$$ \begin{array}{c|rrr}0&4&\color{orangered}{ -3 }&-1\\& & \color{orangered}{0} & \\ \hline &4&\color{orangered}{-3}& \end{array} $$Step 4 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ 0 } \cdot \color{blue}{ \left( -3 \right) } = \color{blue}{ 0 } $.
$$ \begin{array}{c|rrr}\color{blue}{0}&4&-3&-1\\& & 0& \color{blue}{0} \\ \hline &4&\color{blue}{-3}& \end{array} $$Step 5 : Add down last column: $ \color{orangered}{ -1 } + \color{orangered}{ 0 } = \color{orangered}{ -1 } $
$$ \begin{array}{c|rrr}0&4&-3&\color{orangered}{ -1 }\\& & 0& \color{orangered}{0} \\ \hline &\color{blue}{4}&\color{blue}{-3}&\color{orangered}{-1} \end{array} $$Bottom line represents the quotient $ \color{blue}{ 4x-3 } $ with a remainder of $ \color{red}{ -1 } $.