The synthetic division table is:
$$ \begin{array}{c|rr}-5&47&324\\& & \color{black}{-235} \\ \hline &\color{blue}{47}&\color{orangered}{89} \end{array} $$The solution is:
$$ \frac{ 47x+324 }{ x+5 } = \color{blue}{47} ~+~ \frac{ \color{red}{ 89 } }{ x+5 } $$Step 1 : Write down the coefficients of the dividend into division table. Put the zero from $ x + 5 = 0 $ ( $ x = \color{blue}{ -5 } $ ) at the left.
$$ \begin{array}{c|rr}\color{blue}{-5}&47&324\\& & \\ \hline && \end{array} $$Step 1 : Bring down the leading coefficient to the bottom row.
$$ \begin{array}{c|rr}-5&\color{orangered}{ 47 }&324\\& & \\ \hline &\color{orangered}{47}& \end{array} $$Step 2 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ -5 } \cdot \color{blue}{ 47 } = \color{blue}{ -235 } $.
$$ \begin{array}{c|rr}\color{blue}{-5}&47&324\\& & \color{blue}{-235} \\ \hline &\color{blue}{47}& \end{array} $$Step 3 : Add down last column: $ \color{orangered}{ 324 } + \color{orangered}{ \left( -235 \right) } = \color{orangered}{ 89 } $
$$ \begin{array}{c|rr}-5&47&\color{orangered}{ 324 }\\& & \color{orangered}{-235} \\ \hline &\color{blue}{47}&\color{orangered}{89} \end{array} $$Bottom line represents the quotient $ \color{blue}{ 47 } $ with a remainder of $ \color{red}{ 89 } $.