Divide using synthetic division $$ ( 4x ) \div ( x-3 ) $$

The synthetic division table is:

$$ \begin{array}{c|rr}3&4&0\\& & \color{black}{12} \\ \hline &\color{blue}{4}&\color{orangered}{12} \end{array} $$

The solution is:

$$ \frac{ 4x }{ x-3 } = \color{blue}{4} ~+~ \frac{ \color{red}{ 12 } }{ x-3 } $$

Step 1 : Write down the coefficients of the dividend into division table. Put the zero from $ x -3 = 0 $ ( $ x = \color{blue}{ 3 } $ ) at the left.

$$ \begin{array}{c|rr}\color{blue}{3}&4&0\\& & \\ \hline && \end{array} $$

Step 1 : Bring down the leading coefficient to the bottom row.

$$ \begin{array}{c|rr}3&\color{orangered}{ 4 }&0\\& & \\ \hline &\color{orangered}{4}& \end{array} $$

Step 2 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ 3 } \cdot \color{blue}{ 4 } = \color{blue}{ 12 } $.

$$ \begin{array}{c|rr}\color{blue}{3}&4&0\\& & \color{blue}{12} \\ \hline &\color{blue}{4}& \end{array} $$

Step 3 : Add down last column: $ \color{orangered}{ 0 } + \color{orangered}{ 12 } = \color{orangered}{ 12 } $

$$ \begin{array}{c|rr}3&4&\color{orangered}{ 0 }\\& & \color{orangered}{12} \\ \hline &\color{blue}{4}&\color{orangered}{12} \end{array} $$

Bottom line represents the quotient $ \color{blue}{ 4 } $ with a remainder of $ \color{red}{ 12 } $.

Synthetic Division Calculator