The synthetic division table is:
$$ \begin{array}{c|rr}-1&4&4\\& & \color{black}{-4} \\ \hline &\color{blue}{4}&\color{orangered}{0} \end{array} $$The solution is:
$$ \frac{ 4x+4 }{ x+1 } = \color{blue}{4} $$Step 1 : Write down the coefficients of the dividend into division table. Put the zero from $ x + 1 = 0 $ ( $ x = \color{blue}{ -1 } $ ) at the left.
$$ \begin{array}{c|rr}\color{blue}{-1}&4&4\\& & \\ \hline && \end{array} $$Step 1 : Bring down the leading coefficient to the bottom row.
$$ \begin{array}{c|rr}-1&\color{orangered}{ 4 }&4\\& & \\ \hline &\color{orangered}{4}& \end{array} $$Step 2 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ -1 } \cdot \color{blue}{ 4 } = \color{blue}{ -4 } $.
$$ \begin{array}{c|rr}\color{blue}{-1}&4&4\\& & \color{blue}{-4} \\ \hline &\color{blue}{4}& \end{array} $$Step 3 : Add down last column: $ \color{orangered}{ 4 } + \color{orangered}{ \left( -4 \right) } = \color{orangered}{ 0 } $
$$ \begin{array}{c|rr}-1&4&\color{orangered}{ 4 }\\& & \color{orangered}{-4} \\ \hline &\color{blue}{4}&\color{orangered}{0} \end{array} $$Bottom line represents the quotient $ \color{blue}{ 4 } $ with a remainder of $ \color{red}{ 0 } $.