Divide using synthetic division $$ ( 3x^{4}-7x^{3}+7x-14 ) \div ( x-2 ) $$
Answer
The synthetic division table is:
$$ \begin{array}{c|rrrrr}2&3&-7&0&7&-14\\& & 6& -2& -4& \color{black}{6} \\ \hline &\color{blue}{3}&\color{blue}{-1}&\color{blue}{-2}&\color{blue}{3}&\color{orangered}{-8} \end{array} $$The solution is:
$$ \frac{ 3x^{4}-7x^{3}+7x-14 }{ x-2 } = \color{blue}{3x^{3}-x^{2}-2x+3} \color{red}{~-~} \frac{ \color{red}{ 8 } }{ x-2 } $$Explanation
Step 1 : Write down the coefficients of the dividend into division table. Put the zero from $ x -2 = 0 $ ( $ x = \color{blue}{ 2 } $ ) at the left.
$$ \begin{array}{c|rrrrr}\color{blue}{2}&3&-7&0&7&-14\\& & & & & \\ \hline &&&&& \end{array} $$Step 1 : Bring down the leading coefficient to the bottom row.
$$ \begin{array}{c|rrrrr}2&\color{orangered}{ 3 }&-7&0&7&-14\\& & & & & \\ \hline &\color{orangered}{3}&&&& \end{array} $$Step 2 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ 2 } \cdot \color{blue}{ 3 } = \color{blue}{ 6 } $.
$$ \begin{array}{c|rrrrr}\color{blue}{2}&3&-7&0&7&-14\\& & \color{blue}{6} & & & \\ \hline &\color{blue}{3}&&&& \end{array} $$Step 3 : Add down last column: $ \color{orangered}{ -7 } + \color{orangered}{ 6 } = \color{orangered}{ -1 } $
$$ \begin{array}{c|rrrrr}2&3&\color{orangered}{ -7 }&0&7&-14\\& & \color{orangered}{6} & & & \\ \hline &3&\color{orangered}{-1}&&& \end{array} $$Step 4 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ 2 } \cdot \color{blue}{ \left( -1 \right) } = \color{blue}{ -2 } $.
$$ \begin{array}{c|rrrrr}\color{blue}{2}&3&-7&0&7&-14\\& & 6& \color{blue}{-2} & & \\ \hline &3&\color{blue}{-1}&&& \end{array} $$Step 5 : Add down last column: $ \color{orangered}{ 0 } + \color{orangered}{ \left( -2 \right) } = \color{orangered}{ -2 } $
$$ \begin{array}{c|rrrrr}2&3&-7&\color{orangered}{ 0 }&7&-14\\& & 6& \color{orangered}{-2} & & \\ \hline &3&-1&\color{orangered}{-2}&& \end{array} $$Step 6 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ 2 } \cdot \color{blue}{ \left( -2 \right) } = \color{blue}{ -4 } $.
$$ \begin{array}{c|rrrrr}\color{blue}{2}&3&-7&0&7&-14\\& & 6& -2& \color{blue}{-4} & \\ \hline &3&-1&\color{blue}{-2}&& \end{array} $$Step 7 : Add down last column: $ \color{orangered}{ 7 } + \color{orangered}{ \left( -4 \right) } = \color{orangered}{ 3 } $
$$ \begin{array}{c|rrrrr}2&3&-7&0&\color{orangered}{ 7 }&-14\\& & 6& -2& \color{orangered}{-4} & \\ \hline &3&-1&-2&\color{orangered}{3}& \end{array} $$Step 8 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ 2 } \cdot \color{blue}{ 3 } = \color{blue}{ 6 } $.
$$ \begin{array}{c|rrrrr}\color{blue}{2}&3&-7&0&7&-14\\& & 6& -2& -4& \color{blue}{6} \\ \hline &3&-1&-2&\color{blue}{3}& \end{array} $$Step 9 : Add down last column: $ \color{orangered}{ -14 } + \color{orangered}{ 6 } = \color{orangered}{ -8 } $
$$ \begin{array}{c|rrrrr}2&3&-7&0&7&\color{orangered}{ -14 }\\& & 6& -2& -4& \color{orangered}{6} \\ \hline &\color{blue}{3}&\color{blue}{-1}&\color{blue}{-2}&\color{blue}{3}&\color{orangered}{-8} \end{array} $$Bottom line represents the quotient $ \color{blue}{ 3x^{3}-x^{2}-2x+3 } $ with a remainder of $ \color{red}{ -8 } $.