Divide using synthetic division $$ ( 3x^{3}+2x^{2}-11x-4 ) \div ( x+2 ) $$
Answer
The synthetic division table is:
$$ \begin{array}{c|rrrr}-2&3&2&-11&-4\\& & -6& 8& \color{black}{6} \\ \hline &\color{blue}{3}&\color{blue}{-4}&\color{blue}{-3}&\color{orangered}{2} \end{array} $$The solution is:
$$ \frac{ 3x^{3}+2x^{2}-11x-4 }{ x+2 } = \color{blue}{3x^{2}-4x-3} ~+~ \frac{ \color{red}{ 2 } }{ x+2 } $$Explanation
Step 1 : Write down the coefficients of the dividend into division table. Put the zero from $ x + 2 = 0 $ ( $ x = \color{blue}{ -2 } $ ) at the left.
$$ \begin{array}{c|rrrr}\color{blue}{-2}&3&2&-11&-4\\& & & & \\ \hline &&&& \end{array} $$Step 1 : Bring down the leading coefficient to the bottom row.
$$ \begin{array}{c|rrrr}-2&\color{orangered}{ 3 }&2&-11&-4\\& & & & \\ \hline &\color{orangered}{3}&&& \end{array} $$Step 2 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ -2 } \cdot \color{blue}{ 3 } = \color{blue}{ -6 } $.
$$ \begin{array}{c|rrrr}\color{blue}{-2}&3&2&-11&-4\\& & \color{blue}{-6} & & \\ \hline &\color{blue}{3}&&& \end{array} $$Step 3 : Add down last column: $ \color{orangered}{ 2 } + \color{orangered}{ \left( -6 \right) } = \color{orangered}{ -4 } $
$$ \begin{array}{c|rrrr}-2&3&\color{orangered}{ 2 }&-11&-4\\& & \color{orangered}{-6} & & \\ \hline &3&\color{orangered}{-4}&& \end{array} $$Step 4 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ -2 } \cdot \color{blue}{ \left( -4 \right) } = \color{blue}{ 8 } $.
$$ \begin{array}{c|rrrr}\color{blue}{-2}&3&2&-11&-4\\& & -6& \color{blue}{8} & \\ \hline &3&\color{blue}{-4}&& \end{array} $$Step 5 : Add down last column: $ \color{orangered}{ -11 } + \color{orangered}{ 8 } = \color{orangered}{ -3 } $
$$ \begin{array}{c|rrrr}-2&3&2&\color{orangered}{ -11 }&-4\\& & -6& \color{orangered}{8} & \\ \hline &3&-4&\color{orangered}{-3}& \end{array} $$Step 6 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ -2 } \cdot \color{blue}{ \left( -3 \right) } = \color{blue}{ 6 } $.
$$ \begin{array}{c|rrrr}\color{blue}{-2}&3&2&-11&-4\\& & -6& 8& \color{blue}{6} \\ \hline &3&-4&\color{blue}{-3}& \end{array} $$Step 7 : Add down last column: $ \color{orangered}{ -4 } + \color{orangered}{ 6 } = \color{orangered}{ 2 } $
$$ \begin{array}{c|rrrr}-2&3&2&-11&\color{orangered}{ -4 }\\& & -6& 8& \color{orangered}{6} \\ \hline &\color{blue}{3}&\color{blue}{-4}&\color{blue}{-3}&\color{orangered}{2} \end{array} $$Bottom line represents the quotient $ \color{blue}{ 3x^{2}-4x-3 } $ with a remainder of $ \color{red}{ 2 } $.