Divide using synthetic division $$ ( 3x^{2}+7x-20 ) \div ( x-2 ) $$
Answer
The synthetic division table is:
$$ \begin{array}{c|rrr}2&3&7&-20\\& & 6& \color{black}{26} \\ \hline &\color{blue}{3}&\color{blue}{13}&\color{orangered}{6} \end{array} $$The solution is:
$$ \frac{ 3x^{2}+7x-20 }{ x-2 } = \color{blue}{3x+13} ~+~ \frac{ \color{red}{ 6 } }{ x-2 } $$Explanation
Step 1 : Write down the coefficients of the dividend into division table. Put the zero from $ x -2 = 0 $ ( $ x = \color{blue}{ 2 } $ ) at the left.
$$ \begin{array}{c|rrr}\color{blue}{2}&3&7&-20\\& & & \\ \hline &&& \end{array} $$Step 1 : Bring down the leading coefficient to the bottom row.
$$ \begin{array}{c|rrr}2&\color{orangered}{ 3 }&7&-20\\& & & \\ \hline &\color{orangered}{3}&& \end{array} $$Step 2 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ 2 } \cdot \color{blue}{ 3 } = \color{blue}{ 6 } $.
$$ \begin{array}{c|rrr}\color{blue}{2}&3&7&-20\\& & \color{blue}{6} & \\ \hline &\color{blue}{3}&& \end{array} $$Step 3 : Add down last column: $ \color{orangered}{ 7 } + \color{orangered}{ 6 } = \color{orangered}{ 13 } $
$$ \begin{array}{c|rrr}2&3&\color{orangered}{ 7 }&-20\\& & \color{orangered}{6} & \\ \hline &3&\color{orangered}{13}& \end{array} $$Step 4 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ 2 } \cdot \color{blue}{ 13 } = \color{blue}{ 26 } $.
$$ \begin{array}{c|rrr}\color{blue}{2}&3&7&-20\\& & 6& \color{blue}{26} \\ \hline &3&\color{blue}{13}& \end{array} $$Step 5 : Add down last column: $ \color{orangered}{ -20 } + \color{orangered}{ 26 } = \color{orangered}{ 6 } $
$$ \begin{array}{c|rrr}2&3&7&\color{orangered}{ -20 }\\& & 6& \color{orangered}{26} \\ \hline &\color{blue}{3}&\color{blue}{13}&\color{orangered}{6} \end{array} $$Bottom line represents the quotient $ \color{blue}{ 3x+13 } $ with a remainder of $ \color{red}{ 6 } $.