The synthetic division table is:
$$ \begin{array}{c|rr}-3&2&6\\& & \color{black}{-6} \\ \hline &\color{blue}{2}&\color{orangered}{0} \end{array} $$The solution is:
$$ \frac{ 2x+6 }{ x+3 } = \color{blue}{2} $$Step 1 : Write down the coefficients of the dividend into division table. Put the zero from $ x + 3 = 0 $ ( $ x = \color{blue}{ -3 } $ ) at the left.
$$ \begin{array}{c|rr}\color{blue}{-3}&2&6\\& & \\ \hline && \end{array} $$Step 1 : Bring down the leading coefficient to the bottom row.
$$ \begin{array}{c|rr}-3&\color{orangered}{ 2 }&6\\& & \\ \hline &\color{orangered}{2}& \end{array} $$Step 2 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ -3 } \cdot \color{blue}{ 2 } = \color{blue}{ -6 } $.
$$ \begin{array}{c|rr}\color{blue}{-3}&2&6\\& & \color{blue}{-6} \\ \hline &\color{blue}{2}& \end{array} $$Step 3 : Add down last column: $ \color{orangered}{ 6 } + \color{orangered}{ \left( -6 \right) } = \color{orangered}{ 0 } $
$$ \begin{array}{c|rr}-3&2&\color{orangered}{ 6 }\\& & \color{orangered}{-6} \\ \hline &\color{blue}{2}&\color{orangered}{0} \end{array} $$Bottom line represents the quotient $ \color{blue}{ 2 } $ with a remainder of $ \color{red}{ 0 } $.