Divide using synthetic division $$ ( 2x^{3}+3x^{2}-5x+6 ) \div ( x-2 ) $$
Answer
The synthetic division table is:
$$ \begin{array}{c|rrrr}2&2&3&-5&6\\& & 4& 14& \color{black}{18} \\ \hline &\color{blue}{2}&\color{blue}{7}&\color{blue}{9}&\color{orangered}{24} \end{array} $$The solution is:
$$ \frac{ 2x^{3}+3x^{2}-5x+6 }{ x-2 } = \color{blue}{2x^{2}+7x+9} ~+~ \frac{ \color{red}{ 24 } }{ x-2 } $$Explanation
Step 1 : Write down the coefficients of the dividend into division table. Put the zero from $ x -2 = 0 $ ( $ x = \color{blue}{ 2 } $ ) at the left.
$$ \begin{array}{c|rrrr}\color{blue}{2}&2&3&-5&6\\& & & & \\ \hline &&&& \end{array} $$Step 1 : Bring down the leading coefficient to the bottom row.
$$ \begin{array}{c|rrrr}2&\color{orangered}{ 2 }&3&-5&6\\& & & & \\ \hline &\color{orangered}{2}&&& \end{array} $$Step 2 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ 2 } \cdot \color{blue}{ 2 } = \color{blue}{ 4 } $.
$$ \begin{array}{c|rrrr}\color{blue}{2}&2&3&-5&6\\& & \color{blue}{4} & & \\ \hline &\color{blue}{2}&&& \end{array} $$Step 3 : Add down last column: $ \color{orangered}{ 3 } + \color{orangered}{ 4 } = \color{orangered}{ 7 } $
$$ \begin{array}{c|rrrr}2&2&\color{orangered}{ 3 }&-5&6\\& & \color{orangered}{4} & & \\ \hline &2&\color{orangered}{7}&& \end{array} $$Step 4 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ 2 } \cdot \color{blue}{ 7 } = \color{blue}{ 14 } $.
$$ \begin{array}{c|rrrr}\color{blue}{2}&2&3&-5&6\\& & 4& \color{blue}{14} & \\ \hline &2&\color{blue}{7}&& \end{array} $$Step 5 : Add down last column: $ \color{orangered}{ -5 } + \color{orangered}{ 14 } = \color{orangered}{ 9 } $
$$ \begin{array}{c|rrrr}2&2&3&\color{orangered}{ -5 }&6\\& & 4& \color{orangered}{14} & \\ \hline &2&7&\color{orangered}{9}& \end{array} $$Step 6 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ 2 } \cdot \color{blue}{ 9 } = \color{blue}{ 18 } $.
$$ \begin{array}{c|rrrr}\color{blue}{2}&2&3&-5&6\\& & 4& 14& \color{blue}{18} \\ \hline &2&7&\color{blue}{9}& \end{array} $$Step 7 : Add down last column: $ \color{orangered}{ 6 } + \color{orangered}{ 18 } = \color{orangered}{ 24 } $
$$ \begin{array}{c|rrrr}2&2&3&-5&\color{orangered}{ 6 }\\& & 4& 14& \color{orangered}{18} \\ \hline &\color{blue}{2}&\color{blue}{7}&\color{blue}{9}&\color{orangered}{24} \end{array} $$Bottom line represents the quotient $ \color{blue}{ 2x^{2}+7x+9 } $ with a remainder of $ \color{red}{ 24 } $.