The synthetic division table is:
$$ \begin{array}{c|rrrr}2&2&-7&7&-2\\& & 4& -6& \color{black}{2} \\ \hline &\color{blue}{2}&\color{blue}{-3}&\color{blue}{1}&\color{orangered}{0} \end{array} $$The solution is:
$$ \frac{ 2x^{3}-7x^{2}+7x-2 }{ x-2 } = \color{blue}{2x^{2}-3x+1} $$Step 1 : Write down the coefficients of the dividend into division table. Put the zero from $ x -2 = 0 $ ( $ x = \color{blue}{ 2 } $ ) at the left.
$$ \begin{array}{c|rrrr}\color{blue}{2}&2&-7&7&-2\\& & & & \\ \hline &&&& \end{array} $$Step 1 : Bring down the leading coefficient to the bottom row.
$$ \begin{array}{c|rrrr}2&\color{orangered}{ 2 }&-7&7&-2\\& & & & \\ \hline &\color{orangered}{2}&&& \end{array} $$Step 2 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ 2 } \cdot \color{blue}{ 2 } = \color{blue}{ 4 } $.
$$ \begin{array}{c|rrrr}\color{blue}{2}&2&-7&7&-2\\& & \color{blue}{4} & & \\ \hline &\color{blue}{2}&&& \end{array} $$Step 3 : Add down last column: $ \color{orangered}{ -7 } + \color{orangered}{ 4 } = \color{orangered}{ -3 } $
$$ \begin{array}{c|rrrr}2&2&\color{orangered}{ -7 }&7&-2\\& & \color{orangered}{4} & & \\ \hline &2&\color{orangered}{-3}&& \end{array} $$Step 4 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ 2 } \cdot \color{blue}{ \left( -3 \right) } = \color{blue}{ -6 } $.
$$ \begin{array}{c|rrrr}\color{blue}{2}&2&-7&7&-2\\& & 4& \color{blue}{-6} & \\ \hline &2&\color{blue}{-3}&& \end{array} $$Step 5 : Add down last column: $ \color{orangered}{ 7 } + \color{orangered}{ \left( -6 \right) } = \color{orangered}{ 1 } $
$$ \begin{array}{c|rrrr}2&2&-7&\color{orangered}{ 7 }&-2\\& & 4& \color{orangered}{-6} & \\ \hline &2&-3&\color{orangered}{1}& \end{array} $$Step 6 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ 2 } \cdot \color{blue}{ 1 } = \color{blue}{ 2 } $.
$$ \begin{array}{c|rrrr}\color{blue}{2}&2&-7&7&-2\\& & 4& -6& \color{blue}{2} \\ \hline &2&-3&\color{blue}{1}& \end{array} $$Step 7 : Add down last column: $ \color{orangered}{ -2 } + \color{orangered}{ 2 } = \color{orangered}{ 0 } $
$$ \begin{array}{c|rrrr}2&2&-7&7&\color{orangered}{ -2 }\\& & 4& -6& \color{orangered}{2} \\ \hline &\color{blue}{2}&\color{blue}{-3}&\color{blue}{1}&\color{orangered}{0} \end{array} $$Bottom line represents the quotient $ \color{blue}{ 2x^{2}-3x+1 } $ with a remainder of $ \color{red}{ 0 } $.