Divide using synthetic division $$ ( 2x^{2}+11x+14 ) \div ( x+2 ) $$
Answer
The synthetic division table is:
$$ \begin{array}{c|rrr}-2&2&11&14\\& & -4& \color{black}{-14} \\ \hline &\color{blue}{2}&\color{blue}{7}&\color{orangered}{0} \end{array} $$The solution is:
$$ \frac{ 2x^{2}+11x+14 }{ x+2 } = \color{blue}{2x+7} $$Explanation
Step 1 : Write down the coefficients of the dividend into division table. Put the zero from $ x + 2 = 0 $ ( $ x = \color{blue}{ -2 } $ ) at the left.
$$ \begin{array}{c|rrr}\color{blue}{-2}&2&11&14\\& & & \\ \hline &&& \end{array} $$Step 1 : Bring down the leading coefficient to the bottom row.
$$ \begin{array}{c|rrr}-2&\color{orangered}{ 2 }&11&14\\& & & \\ \hline &\color{orangered}{2}&& \end{array} $$Step 2 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ -2 } \cdot \color{blue}{ 2 } = \color{blue}{ -4 } $.
$$ \begin{array}{c|rrr}\color{blue}{-2}&2&11&14\\& & \color{blue}{-4} & \\ \hline &\color{blue}{2}&& \end{array} $$Step 3 : Add down last column: $ \color{orangered}{ 11 } + \color{orangered}{ \left( -4 \right) } = \color{orangered}{ 7 } $
$$ \begin{array}{c|rrr}-2&2&\color{orangered}{ 11 }&14\\& & \color{orangered}{-4} & \\ \hline &2&\color{orangered}{7}& \end{array} $$Step 4 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ -2 } \cdot \color{blue}{ 7 } = \color{blue}{ -14 } $.
$$ \begin{array}{c|rrr}\color{blue}{-2}&2&11&14\\& & -4& \color{blue}{-14} \\ \hline &2&\color{blue}{7}& \end{array} $$Step 5 : Add down last column: $ \color{orangered}{ 14 } + \color{orangered}{ \left( -14 \right) } = \color{orangered}{ 0 } $
$$ \begin{array}{c|rrr}-2&2&11&\color{orangered}{ 14 }\\& & -4& \color{orangered}{-14} \\ \hline &\color{blue}{2}&\color{blue}{7}&\color{orangered}{0} \end{array} $$Bottom line represents the quotient $ \color{blue}{ 2x+7 } $ with a remainder of $ \color{red}{ 0 } $.