Divide using synthetic division $$ ( 2x^{2}-9x-5 ) \div ( x-5 ) $$
Answer
The synthetic division table is:
$$ \begin{array}{c|rrr}5&2&-9&-5\\& & 10& \color{black}{5} \\ \hline &\color{blue}{2}&\color{blue}{1}&\color{orangered}{0} \end{array} $$The solution is:
$$ \frac{ 2x^{2}-9x-5 }{ x-5 } = \color{blue}{2x+1} $$Explanation
Step 1 : Write down the coefficients of the dividend into division table. Put the zero from $ x -5 = 0 $ ( $ x = \color{blue}{ 5 } $ ) at the left.
$$ \begin{array}{c|rrr}\color{blue}{5}&2&-9&-5\\& & & \\ \hline &&& \end{array} $$Step 1 : Bring down the leading coefficient to the bottom row.
$$ \begin{array}{c|rrr}5&\color{orangered}{ 2 }&-9&-5\\& & & \\ \hline &\color{orangered}{2}&& \end{array} $$Step 2 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ 5 } \cdot \color{blue}{ 2 } = \color{blue}{ 10 } $.
$$ \begin{array}{c|rrr}\color{blue}{5}&2&-9&-5\\& & \color{blue}{10} & \\ \hline &\color{blue}{2}&& \end{array} $$Step 3 : Add down last column: $ \color{orangered}{ -9 } + \color{orangered}{ 10 } = \color{orangered}{ 1 } $
$$ \begin{array}{c|rrr}5&2&\color{orangered}{ -9 }&-5\\& & \color{orangered}{10} & \\ \hline &2&\color{orangered}{1}& \end{array} $$Step 4 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ 5 } \cdot \color{blue}{ 1 } = \color{blue}{ 5 } $.
$$ \begin{array}{c|rrr}\color{blue}{5}&2&-9&-5\\& & 10& \color{blue}{5} \\ \hline &2&\color{blue}{1}& \end{array} $$Step 5 : Add down last column: $ \color{orangered}{ -5 } + \color{orangered}{ 5 } = \color{orangered}{ 0 } $
$$ \begin{array}{c|rrr}5&2&-9&\color{orangered}{ -5 }\\& & 10& \color{orangered}{5} \\ \hline &\color{blue}{2}&\color{blue}{1}&\color{orangered}{0} \end{array} $$Bottom line represents the quotient $ \color{blue}{ 2x+1 } $ with a remainder of $ \color{red}{ 0 } $.