Divide using synthetic division $$ ( -2x^{2}-8x+9 ) \div ( x+2 ) $$
Answer
The synthetic division table is:
$$ \begin{array}{c|rrr}-2&-2&-8&9\\& & 4& \color{black}{8} \\ \hline &\color{blue}{-2}&\color{blue}{-4}&\color{orangered}{17} \end{array} $$The solution is:
$$ \frac{ -2x^{2}-8x+9 }{ x+2 } = \color{blue}{-2x-4} ~+~ \frac{ \color{red}{ 17 } }{ x+2 } $$Explanation
Step 1 : Write down the coefficients of the dividend into division table. Put the zero from $ x + 2 = 0 $ ( $ x = \color{blue}{ -2 } $ ) at the left.
$$ \begin{array}{c|rrr}\color{blue}{-2}&-2&-8&9\\& & & \\ \hline &&& \end{array} $$Step 1 : Bring down the leading coefficient to the bottom row.
$$ \begin{array}{c|rrr}-2&\color{orangered}{ -2 }&-8&9\\& & & \\ \hline &\color{orangered}{-2}&& \end{array} $$Step 2 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ -2 } \cdot \color{blue}{ \left( -2 \right) } = \color{blue}{ 4 } $.
$$ \begin{array}{c|rrr}\color{blue}{-2}&-2&-8&9\\& & \color{blue}{4} & \\ \hline &\color{blue}{-2}&& \end{array} $$Step 3 : Add down last column: $ \color{orangered}{ -8 } + \color{orangered}{ 4 } = \color{orangered}{ -4 } $
$$ \begin{array}{c|rrr}-2&-2&\color{orangered}{ -8 }&9\\& & \color{orangered}{4} & \\ \hline &-2&\color{orangered}{-4}& \end{array} $$Step 4 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ -2 } \cdot \color{blue}{ \left( -4 \right) } = \color{blue}{ 8 } $.
$$ \begin{array}{c|rrr}\color{blue}{-2}&-2&-8&9\\& & 4& \color{blue}{8} \\ \hline &-2&\color{blue}{-4}& \end{array} $$Step 5 : Add down last column: $ \color{orangered}{ 9 } + \color{orangered}{ 8 } = \color{orangered}{ 17 } $
$$ \begin{array}{c|rrr}-2&-2&-8&\color{orangered}{ 9 }\\& & 4& \color{orangered}{8} \\ \hline &\color{blue}{-2}&\color{blue}{-4}&\color{orangered}{17} \end{array} $$Bottom line represents the quotient $ \color{blue}{ -2x-4 } $ with a remainder of $ \color{red}{ 17 } $.