Divide using synthetic division $$ ( 2x^{2}-4x ) \div ( x-3 ) $$
Answer
The synthetic division table is:
$$ \begin{array}{c|rrr}3&2&-4&0\\& & 6& \color{black}{6} \\ \hline &\color{blue}{2}&\color{blue}{2}&\color{orangered}{6} \end{array} $$The solution is:
$$ \frac{ 2x^{2}-4x }{ x-3 } = \color{blue}{2x+2} ~+~ \frac{ \color{red}{ 6 } }{ x-3 } $$Explanation
Step 1 : Write down the coefficients of the dividend into division table. Put the zero from $ x -3 = 0 $ ( $ x = \color{blue}{ 3 } $ ) at the left.
$$ \begin{array}{c|rrr}\color{blue}{3}&2&-4&0\\& & & \\ \hline &&& \end{array} $$Step 1 : Bring down the leading coefficient to the bottom row.
$$ \begin{array}{c|rrr}3&\color{orangered}{ 2 }&-4&0\\& & & \\ \hline &\color{orangered}{2}&& \end{array} $$Step 2 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ 3 } \cdot \color{blue}{ 2 } = \color{blue}{ 6 } $.
$$ \begin{array}{c|rrr}\color{blue}{3}&2&-4&0\\& & \color{blue}{6} & \\ \hline &\color{blue}{2}&& \end{array} $$Step 3 : Add down last column: $ \color{orangered}{ -4 } + \color{orangered}{ 6 } = \color{orangered}{ 2 } $
$$ \begin{array}{c|rrr}3&2&\color{orangered}{ -4 }&0\\& & \color{orangered}{6} & \\ \hline &2&\color{orangered}{2}& \end{array} $$Step 4 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ 3 } \cdot \color{blue}{ 2 } = \color{blue}{ 6 } $.
$$ \begin{array}{c|rrr}\color{blue}{3}&2&-4&0\\& & 6& \color{blue}{6} \\ \hline &2&\color{blue}{2}& \end{array} $$Step 5 : Add down last column: $ \color{orangered}{ 0 } + \color{orangered}{ 6 } = \color{orangered}{ 6 } $
$$ \begin{array}{c|rrr}3&2&-4&\color{orangered}{ 0 }\\& & 6& \color{orangered}{6} \\ \hline &\color{blue}{2}&\color{blue}{2}&\color{orangered}{6} \end{array} $$Bottom line represents the quotient $ \color{blue}{ 2x+2 } $ with a remainder of $ \color{red}{ 6 } $.