Divide using synthetic division $$ ( 27x^{3}-3x+5 ) \div ( x-2 ) $$
Answer
The synthetic division table is:
$$ \begin{array}{c|rrrr}2&27&0&-3&5\\& & 54& 108& \color{black}{210} \\ \hline &\color{blue}{27}&\color{blue}{54}&\color{blue}{105}&\color{orangered}{215} \end{array} $$The solution is:
$$ \frac{ 27x^{3}-3x+5 }{ x-2 } = \color{blue}{27x^{2}+54x+105} ~+~ \frac{ \color{red}{ 215 } }{ x-2 } $$Explanation
Step 1 : Write down the coefficients of the dividend into division table. Put the zero from $ x -2 = 0 $ ( $ x = \color{blue}{ 2 } $ ) at the left.
$$ \begin{array}{c|rrrr}\color{blue}{2}&27&0&-3&5\\& & & & \\ \hline &&&& \end{array} $$Step 1 : Bring down the leading coefficient to the bottom row.
$$ \begin{array}{c|rrrr}2&\color{orangered}{ 27 }&0&-3&5\\& & & & \\ \hline &\color{orangered}{27}&&& \end{array} $$Step 2 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ 2 } \cdot \color{blue}{ 27 } = \color{blue}{ 54 } $.
$$ \begin{array}{c|rrrr}\color{blue}{2}&27&0&-3&5\\& & \color{blue}{54} & & \\ \hline &\color{blue}{27}&&& \end{array} $$Step 3 : Add down last column: $ \color{orangered}{ 0 } + \color{orangered}{ 54 } = \color{orangered}{ 54 } $
$$ \begin{array}{c|rrrr}2&27&\color{orangered}{ 0 }&-3&5\\& & \color{orangered}{54} & & \\ \hline &27&\color{orangered}{54}&& \end{array} $$Step 4 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ 2 } \cdot \color{blue}{ 54 } = \color{blue}{ 108 } $.
$$ \begin{array}{c|rrrr}\color{blue}{2}&27&0&-3&5\\& & 54& \color{blue}{108} & \\ \hline &27&\color{blue}{54}&& \end{array} $$Step 5 : Add down last column: $ \color{orangered}{ -3 } + \color{orangered}{ 108 } = \color{orangered}{ 105 } $
$$ \begin{array}{c|rrrr}2&27&0&\color{orangered}{ -3 }&5\\& & 54& \color{orangered}{108} & \\ \hline &27&54&\color{orangered}{105}& \end{array} $$Step 6 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ 2 } \cdot \color{blue}{ 105 } = \color{blue}{ 210 } $.
$$ \begin{array}{c|rrrr}\color{blue}{2}&27&0&-3&5\\& & 54& 108& \color{blue}{210} \\ \hline &27&54&\color{blue}{105}& \end{array} $$Step 7 : Add down last column: $ \color{orangered}{ 5 } + \color{orangered}{ 210 } = \color{orangered}{ 215 } $
$$ \begin{array}{c|rrrr}2&27&0&-3&\color{orangered}{ 5 }\\& & 54& 108& \color{orangered}{210} \\ \hline &\color{blue}{27}&\color{blue}{54}&\color{blue}{105}&\color{orangered}{215} \end{array} $$Bottom line represents the quotient $ \color{blue}{ 27x^{2}+54x+105 } $ with a remainder of $ \color{red}{ 215 } $.