Divide using synthetic division $$ ( 10x^{2}-19x-13 ) \div ( 5x+1 ) $$
Answer
The synthetic division table is:
$$ \begin{array}{c|rrr}-1&10&-19&-13\\& & -10& \color{black}{29} \\ \hline &\color{blue}{10}&\color{blue}{-29}&\color{orangered}{16} \end{array} $$The solution is:
$$ \frac{ 10x^{2}-19x-13 }{ x+1 } = \color{blue}{10x-29} ~+~ \frac{ \color{red}{ 16 } }{ x+1 } $$Explanation
Step 1 : Write down the coefficients of the dividend into division table. Put the zero from $ x + 1 = 0 $ ( $ x = \color{blue}{ -1 } $ ) at the left.
$$ \begin{array}{c|rrr}\color{blue}{-1}&10&-19&-13\\& & & \\ \hline &&& \end{array} $$Step 1 : Bring down the leading coefficient to the bottom row.
$$ \begin{array}{c|rrr}-1&\color{orangered}{ 10 }&-19&-13\\& & & \\ \hline &\color{orangered}{10}&& \end{array} $$Step 2 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ -1 } \cdot \color{blue}{ 10 } = \color{blue}{ -10 } $.
$$ \begin{array}{c|rrr}\color{blue}{-1}&10&-19&-13\\& & \color{blue}{-10} & \\ \hline &\color{blue}{10}&& \end{array} $$Step 3 : Add down last column: $ \color{orangered}{ -19 } + \color{orangered}{ \left( -10 \right) } = \color{orangered}{ -29 } $
$$ \begin{array}{c|rrr}-1&10&\color{orangered}{ -19 }&-13\\& & \color{orangered}{-10} & \\ \hline &10&\color{orangered}{-29}& \end{array} $$Step 4 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ -1 } \cdot \color{blue}{ \left( -29 \right) } = \color{blue}{ 29 } $.
$$ \begin{array}{c|rrr}\color{blue}{-1}&10&-19&-13\\& & -10& \color{blue}{29} \\ \hline &10&\color{blue}{-29}& \end{array} $$Step 5 : Add down last column: $ \color{orangered}{ -13 } + \color{orangered}{ 29 } = \color{orangered}{ 16 } $
$$ \begin{array}{c|rrr}-1&10&-19&\color{orangered}{ -13 }\\& & -10& \color{orangered}{29} \\ \hline &\color{blue}{10}&\color{blue}{-29}&\color{orangered}{16} \end{array} $$Bottom line represents the quotient $ \color{blue}{ 10x-29 } $ with a remainder of $ \color{red}{ 16 } $.