Divide using synthetic division $$ ( -x^{5}+x^{4}+16x-16 ) \div ( -1 ) $$
Answer
The synthetic division table is:
$$ \begin{array}{c|rrrrrr}0&-1&1&0&0&16&-16\\& & 0& 0& 0& 0& \color{black}{0} \\ \hline &\color{blue}{-1}&\color{blue}{1}&\color{blue}{0}&\color{blue}{0}&\color{blue}{16}&\color{orangered}{-16} \end{array} $$The solution is:
$$ \frac{ -x^{5}+x^{4}+16x-16 }{ x } = \color{blue}{-x^{4}+x^{3}+16} \color{red}{~-~} \frac{ \color{red}{ 16 } }{ x } $$Explanation
Step 1 : Write down the coefficients of the dividend into division table.Put the zero at the left.
$$ \begin{array}{c|rrrrrr}\color{blue}{0}&-1&1&0&0&16&-16\\& & & & & & \\ \hline &&&&&& \end{array} $$Step 1 : Bring down the leading coefficient to the bottom row.
$$ \begin{array}{c|rrrrrr}0&\color{orangered}{ -1 }&1&0&0&16&-16\\& & & & & & \\ \hline &\color{orangered}{-1}&&&&& \end{array} $$Step 2 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ 0 } \cdot \color{blue}{ \left( -1 \right) } = \color{blue}{ 0 } $.
$$ \begin{array}{c|rrrrrr}\color{blue}{0}&-1&1&0&0&16&-16\\& & \color{blue}{0} & & & & \\ \hline &\color{blue}{-1}&&&&& \end{array} $$Step 3 : Add down last column: $ \color{orangered}{ 1 } + \color{orangered}{ 0 } = \color{orangered}{ 1 } $
$$ \begin{array}{c|rrrrrr}0&-1&\color{orangered}{ 1 }&0&0&16&-16\\& & \color{orangered}{0} & & & & \\ \hline &-1&\color{orangered}{1}&&&& \end{array} $$Step 4 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ 0 } \cdot \color{blue}{ 1 } = \color{blue}{ 0 } $.
$$ \begin{array}{c|rrrrrr}\color{blue}{0}&-1&1&0&0&16&-16\\& & 0& \color{blue}{0} & & & \\ \hline &-1&\color{blue}{1}&&&& \end{array} $$Step 5 : Add down last column: $ \color{orangered}{ 0 } + \color{orangered}{ 0 } = \color{orangered}{ 0 } $
$$ \begin{array}{c|rrrrrr}0&-1&1&\color{orangered}{ 0 }&0&16&-16\\& & 0& \color{orangered}{0} & & & \\ \hline &-1&1&\color{orangered}{0}&&& \end{array} $$Step 6 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ 0 } \cdot \color{blue}{ 0 } = \color{blue}{ 0 } $.
$$ \begin{array}{c|rrrrrr}\color{blue}{0}&-1&1&0&0&16&-16\\& & 0& 0& \color{blue}{0} & & \\ \hline &-1&1&\color{blue}{0}&&& \end{array} $$Step 7 : Add down last column: $ \color{orangered}{ 0 } + \color{orangered}{ 0 } = \color{orangered}{ 0 } $
$$ \begin{array}{c|rrrrrr}0&-1&1&0&\color{orangered}{ 0 }&16&-16\\& & 0& 0& \color{orangered}{0} & & \\ \hline &-1&1&0&\color{orangered}{0}&& \end{array} $$Step 8 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ 0 } \cdot \color{blue}{ 0 } = \color{blue}{ 0 } $.
$$ \begin{array}{c|rrrrrr}\color{blue}{0}&-1&1&0&0&16&-16\\& & 0& 0& 0& \color{blue}{0} & \\ \hline &-1&1&0&\color{blue}{0}&& \end{array} $$Step 9 : Add down last column: $ \color{orangered}{ 16 } + \color{orangered}{ 0 } = \color{orangered}{ 16 } $
$$ \begin{array}{c|rrrrrr}0&-1&1&0&0&\color{orangered}{ 16 }&-16\\& & 0& 0& 0& \color{orangered}{0} & \\ \hline &-1&1&0&0&\color{orangered}{16}& \end{array} $$Step 10 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ 0 } \cdot \color{blue}{ 16 } = \color{blue}{ 0 } $.
$$ \begin{array}{c|rrrrrr}\color{blue}{0}&-1&1&0&0&16&-16\\& & 0& 0& 0& 0& \color{blue}{0} \\ \hline &-1&1&0&0&\color{blue}{16}& \end{array} $$Step 11 : Add down last column: $ \color{orangered}{ -16 } + \color{orangered}{ 0 } = \color{orangered}{ -16 } $
$$ \begin{array}{c|rrrrrr}0&-1&1&0&0&16&\color{orangered}{ -16 }\\& & 0& 0& 0& 0& \color{orangered}{0} \\ \hline &\color{blue}{-1}&\color{blue}{1}&\color{blue}{0}&\color{blue}{0}&\color{blue}{16}&\color{orangered}{-16} \end{array} $$Bottom line represents the quotient $ \color{blue}{ -x^{4}+x^{3}+16 } $ with a remainder of $ \color{red}{ -16 } $.