The synthetic division table is:
$$ \begin{array}{c|rr}3&-5&0\\& & \color{black}{-15} \\ \hline &\color{blue}{-5}&\color{orangered}{-15} \end{array} $$The solution is:
$$ \frac{ -5x }{ x-3 } = \color{blue}{-5} \color{red}{~-~} \frac{ \color{red}{ 15 } }{ x-3 } $$Step 1 : Write down the coefficients of the dividend into division table. Put the zero from $ x -3 = 0 $ ( $ x = \color{blue}{ 3 } $ ) at the left.
$$ \begin{array}{c|rr}\color{blue}{3}&-5&0\\& & \\ \hline && \end{array} $$Step 1 : Bring down the leading coefficient to the bottom row.
$$ \begin{array}{c|rr}3&\color{orangered}{ -5 }&0\\& & \\ \hline &\color{orangered}{-5}& \end{array} $$Step 2 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ 3 } \cdot \color{blue}{ \left( -5 \right) } = \color{blue}{ -15 } $.
$$ \begin{array}{c|rr}\color{blue}{3}&-5&0\\& & \color{blue}{-15} \\ \hline &\color{blue}{-5}& \end{array} $$Step 3 : Add down last column: $ \color{orangered}{ 0 } + \color{orangered}{ \left( -15 \right) } = \color{orangered}{ -15 } $
$$ \begin{array}{c|rr}3&-5&\color{orangered}{ 0 }\\& & \color{orangered}{-15} \\ \hline &\color{blue}{-5}&\color{orangered}{-15} \end{array} $$Bottom line represents the quotient $ \color{blue}{ -5 } $ with a remainder of $ \color{red}{ -15 } $.