The synthetic division table is:
$$ \begin{array}{c|rr}0&\frac{ 49 }{ 10 }&-3\\& & \color{black}{0} \\ \hline &\color{blue}{\frac{ 49 }{ 10 }}&\color{orangered}{-3} \end{array} $$The solution is:
$$ \frac{ \frac{ 49 }{ 10 }x-3 }{ x } = \color{blue}{\frac{ 49 }{ 10 }} \color{red}{~-~} \frac{ \color{red}{ 3 } }{ x } $$Step 1 : Write down the coefficients of the dividend into division table.Put the zero at the left.
$$ \begin{array}{c|rr}\color{blue}{0}&\frac{ 49 }{ 10 }&-3\\& & \\ \hline && \end{array} $$Step 1 : Bring down the leading coefficient to the bottom row.
$$ \begin{array}{c|rr}0&\color{orangered}{ \frac{ 49 }{ 10 } }&-3\\& & \\ \hline &\color{orangered}{\frac{ 49 }{ 10 }}& \end{array} $$Step 2 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ 0 } \cdot \color{blue}{ \frac{ 49 }{ 10 } } = \color{blue}{ 0 } $.
$$ \begin{array}{c|rr}\color{blue}{0}&\frac{ 49 }{ 10 }&-3\\& & \color{blue}{0} \\ \hline &\color{blue}{\frac{ 49 }{ 10 }}& \end{array} $$Step 3 : Add down last column: $ \color{orangered}{ -3 } + \color{orangered}{ 0 } = \color{orangered}{ -3 } $
$$ \begin{array}{c|rr}0&\frac{ 49 }{ 10 }&\color{orangered}{ -3 }\\& & \color{orangered}{0} \\ \hline &\color{blue}{\frac{ 49 }{ 10 }}&\color{orangered}{-3} \end{array} $$Bottom line represents the quotient $ \color{blue}{ \frac{ 49 }{ 10 } } $ with a remainder of $ \color{red}{ -3 } $.