Divide using synthetic division $$ ( 12x^{2}+20x-96 ) \div ( -2 ) $$
Answer
The synthetic division table is:
$$ \begin{array}{c|rrr}0&12&20&-96\\& & 0& \color{black}{0} \\ \hline &\color{blue}{12}&\color{blue}{20}&\color{orangered}{-96} \end{array} $$The solution is:
$$ \frac{ 12x^{2}+20x-96 }{ x } = \color{blue}{12x+20} \color{red}{~-~} \frac{ \color{red}{ 96 } }{ x } $$Explanation
Step 1 : Write down the coefficients of the dividend into division table.Put the zero at the left.
$$ \begin{array}{c|rrr}\color{blue}{0}&12&20&-96\\& & & \\ \hline &&& \end{array} $$Step 1 : Bring down the leading coefficient to the bottom row.
$$ \begin{array}{c|rrr}0&\color{orangered}{ 12 }&20&-96\\& & & \\ \hline &\color{orangered}{12}&& \end{array} $$Step 2 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ 0 } \cdot \color{blue}{ 12 } = \color{blue}{ 0 } $.
$$ \begin{array}{c|rrr}\color{blue}{0}&12&20&-96\\& & \color{blue}{0} & \\ \hline &\color{blue}{12}&& \end{array} $$Step 3 : Add down last column: $ \color{orangered}{ 20 } + \color{orangered}{ 0 } = \color{orangered}{ 20 } $
$$ \begin{array}{c|rrr}0&12&\color{orangered}{ 20 }&-96\\& & \color{orangered}{0} & \\ \hline &12&\color{orangered}{20}& \end{array} $$Step 4 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ 0 } \cdot \color{blue}{ 20 } = \color{blue}{ 0 } $.
$$ \begin{array}{c|rrr}\color{blue}{0}&12&20&-96\\& & 0& \color{blue}{0} \\ \hline &12&\color{blue}{20}& \end{array} $$Step 5 : Add down last column: $ \color{orangered}{ -96 } + \color{orangered}{ 0 } = \color{orangered}{ -96 } $
$$ \begin{array}{c|rrr}0&12&20&\color{orangered}{ -96 }\\& & 0& \color{orangered}{0} \\ \hline &\color{blue}{12}&\color{blue}{20}&\color{orangered}{-96} \end{array} $$Bottom line represents the quotient $ \color{blue}{ 12x+20 } $ with a remainder of $ \color{red}{ -96 } $.