Divide using synthetic division $$ ( -3x^{2}+20x-20 ) \div ( -3 ) $$
Answer
The synthetic division table is:
$$ \begin{array}{c|rrr}0&-3&20&-20\\& & 0& \color{black}{0} \\ \hline &\color{blue}{-3}&\color{blue}{20}&\color{orangered}{-20} \end{array} $$The solution is:
$$ \frac{ -3x^{2}+20x-20 }{ x } = \color{blue}{-3x+20} \color{red}{~-~} \frac{ \color{red}{ 20 } }{ x } $$Explanation
Step 1 : Write down the coefficients of the dividend into division table.Put the zero at the left.
$$ \begin{array}{c|rrr}\color{blue}{0}&-3&20&-20\\& & & \\ \hline &&& \end{array} $$Step 1 : Bring down the leading coefficient to the bottom row.
$$ \begin{array}{c|rrr}0&\color{orangered}{ -3 }&20&-20\\& & & \\ \hline &\color{orangered}{-3}&& \end{array} $$Step 2 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ 0 } \cdot \color{blue}{ \left( -3 \right) } = \color{blue}{ 0 } $.
$$ \begin{array}{c|rrr}\color{blue}{0}&-3&20&-20\\& & \color{blue}{0} & \\ \hline &\color{blue}{-3}&& \end{array} $$Step 3 : Add down last column: $ \color{orangered}{ 20 } + \color{orangered}{ 0 } = \color{orangered}{ 20 } $
$$ \begin{array}{c|rrr}0&-3&\color{orangered}{ 20 }&-20\\& & \color{orangered}{0} & \\ \hline &-3&\color{orangered}{20}& \end{array} $$Step 4 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ 0 } \cdot \color{blue}{ 20 } = \color{blue}{ 0 } $.
$$ \begin{array}{c|rrr}\color{blue}{0}&-3&20&-20\\& & 0& \color{blue}{0} \\ \hline &-3&\color{blue}{20}& \end{array} $$Step 5 : Add down last column: $ \color{orangered}{ -20 } + \color{orangered}{ 0 } = \color{orangered}{ -20 } $
$$ \begin{array}{c|rrr}0&-3&20&\color{orangered}{ -20 }\\& & 0& \color{orangered}{0} \\ \hline &\color{blue}{-3}&\color{blue}{20}&\color{orangered}{-20} \end{array} $$Bottom line represents the quotient $ \color{blue}{ -3x+20 } $ with a remainder of $ \color{red}{ -20 } $.