The synthetic division table is:
$$ \begin{array}{c|rr}-2&7&2\\& & \color{black}{-14} \\ \hline &\color{blue}{7}&\color{orangered}{-12} \end{array} $$The solution is:
$$ \frac{ 7x+2 }{ x+2 } = \color{blue}{7} \color{red}{~-~} \frac{ \color{red}{ 12 } }{ x+2 } $$Step 1 : Write down the coefficients of the dividend into division table. Put the zero from $ x + 2 = 0 $ ( $ x = \color{blue}{ -2 } $ ) at the left.
$$ \begin{array}{c|rr}\color{blue}{-2}&7&2\\& & \\ \hline && \end{array} $$Step 1 : Bring down the leading coefficient to the bottom row.
$$ \begin{array}{c|rr}-2&\color{orangered}{ 7 }&2\\& & \\ \hline &\color{orangered}{7}& \end{array} $$Step 2 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ -2 } \cdot \color{blue}{ 7 } = \color{blue}{ -14 } $.
$$ \begin{array}{c|rr}\color{blue}{-2}&7&2\\& & \color{blue}{-14} \\ \hline &\color{blue}{7}& \end{array} $$Step 3 : Add down last column: $ \color{orangered}{ 2 } + \color{orangered}{ \left( -14 \right) } = \color{orangered}{ -12 } $
$$ \begin{array}{c|rr}-2&7&\color{orangered}{ 2 }\\& & \color{orangered}{-14} \\ \hline &\color{blue}{7}&\color{orangered}{-12} \end{array} $$Bottom line represents the quotient $ \color{blue}{ 7 } $ with a remainder of $ \color{red}{ -12 } $.