Find the angle $ \gamma $ of a triangle if angle $\alpha = 52^o$ and angle $\beta = 71^o$.
Answer
$\gamma = 57^o$
Explanation
To find angle $ \gamma $ use formula:
$$ \alpha + \beta + \gamma = 180^o $$After substituting $ \alpha = 52^o $ and $ \beta = 71^o $ we have:
$$ 52^o + 71^o + \gamma = 180^o $$ $$ \gamma + 123^o = 180^o $$ $$ \gamma = 180^o - 123^o $$ $$ \gamma = 57^o $$This page was created using
Oblique Triangle Calculator