Question
Answer
$$\sqrt{3}\cdot\sqrt{27}=9$$
Explanation
| $$ \begin{aligned}\sqrt{3}\cdot\sqrt{27}& \xlongequal{ }\sqrt{81} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}9\end{aligned} $$ | |
| ① | The square root of $ 81 $ is $ 9 $. |
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