Question
Answer
$$\sqrt{13}\cdot(4+\sqrt{13})=4\sqrt{13}+13$$
Explanation
| $$ \begin{aligned}\sqrt{13}\cdot(4+\sqrt{13})& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}4\sqrt{13}+13\end{aligned} $$ | |
| ① | $$ \color{blue}{ \sqrt{13} } \cdot \left( 4 + \sqrt{13}\right) = \color{blue}{ \sqrt{13}} \cdot4+\color{blue}{ \sqrt{13}} \cdot \sqrt{13} = \\ = 4 \sqrt{13} + 13 $$ |
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