Question
Answer
$$\sqrt{12}-\sqrt{48}+\sqrt{3}=-\sqrt{3}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}\sqrt{12}-\sqrt{48}+\sqrt{3}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}2\sqrt{3}-4\sqrt{3}+\sqrt{3} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}-\sqrt{3}\end{aligned} $$ | |
| ① | $$ \sqrt{12} =
\sqrt{ 2 ^2 \cdot 3 } =
\sqrt{ 2 ^2 } \, \sqrt{ 3 } =
2 \sqrt{ 3 }$$ |
| ② | $$ - \sqrt{48} =
- \sqrt{ 4 ^2 \cdot 3 } =
- \sqrt{ 4 ^2 } \, \sqrt{ 3 } =
- 4 \sqrt{ 3 }$$ |
| ③ | Combine like terms |
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