Question
Answer
$$\sqrt{6-5}^2+(7-10)^2=\sqrt{6-5}^2+9$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}\sqrt{6-5}^2+(7-10)^2& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\sqrt{6-5}^2+(-3)^2 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\sqrt{6-5}^2+9\end{aligned} $$ | |
| ① | Combine like terms |
| ② | $ (-3) ^ 2 = 9 $ |
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