Question
Answer
$$8\sqrt{2}-4\sqrt{8}+\sqrt{32}=4\sqrt{2}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}8\sqrt{2}-4\sqrt{8}+\sqrt{32}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}8\sqrt{2}-8\sqrt{2}+4\sqrt{2} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}4\sqrt{2}\end{aligned} $$ | |
| ① | $$ - 4 \sqrt{8} =
-4 \sqrt{ 2 ^2 \cdot 2 } =
-4 \sqrt{ 2 ^2 } \, \sqrt{ 2 } =
-4 \cdot 2 \sqrt{ 2 } =
-8 \sqrt{ 2 } $$ |
| ② | $$ \sqrt{32} =
\sqrt{ 4 ^2 \cdot 2 } =
\sqrt{ 4 ^2 } \, \sqrt{ 2 } =
4 \sqrt{ 2 }$$ |
| ③ | Combine like terms |
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