Answer
$$-8\sqrt{128}=-64\sqrt{2}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}-8\sqrt{128}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-8\cdot \sqrt{ 64 \cdot 2 } \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}-8\cdot \sqrt{ 64 } \cdot \sqrt{ 2 } \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}-8\cdot8 \sqrt{ 2 } \xlongequal{ } \\[1 em] & \xlongequal{ }-64\sqrt{2}\end{aligned} $$ | |
| ① | Factor out the largest perfect square of 128. ( in this example we factored out $ 64 $ ) |
| ② | Rewrite $ \sqrt{ 64 \cdot 2 } $ as the product of two radicals. |
| ③ | The square root of $ 64 $ is $ 8 $. |
This page was created using
Simplify Radical Expression