Answer
$$\frac{\sqrt{27}-\sqrt{8}}{\sqrt{3}+\sqrt{2}-\frac{\sqrt{6}}{\sqrt{3}+\sqrt{2}}}-\frac{\sqrt{27}+\sqrt{8}}{\sqrt{3}-\sqrt{2}+\frac{\sqrt{6}}{\sqrt{3}-\sqrt{2}}}=\frac{3\sqrt{3}-2\sqrt{2}}{\sqrt{3}+\sqrt{2}-\frac{\sqrt{6}}{\sqrt{3}+\sqrt{2}}}-\frac{3\sqrt{3}+2\sqrt{2}}{\sqrt{3}-\sqrt{2}+\frac{\sqrt{6}}{\sqrt{3}-\sqrt{2}}}$$
Explanation
This page was created using
Simplify Radical Expression