Question
Answer
$$(6-9\sqrt{77})\cdot(-10-5\sqrt{21})=-60-30\sqrt{21}+90\sqrt{77}+315\sqrt{33}$$
Explanation
| $$ \begin{aligned}(6-9\sqrt{77})\cdot(-10-5\sqrt{21})& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-60-30\sqrt{21}+90\sqrt{77}+315\sqrt{33}\end{aligned} $$ | |
| ① | $$ \color{blue}{ \left( 6- 9 \sqrt{77}\right) } \cdot \left( -10- 5 \sqrt{21}\right) = \color{blue}{6} \cdot-10+\color{blue}{6} \cdot- 5 \sqrt{21}\color{blue}{- 9 \sqrt{77}} \cdot-10\color{blue}{- 9 \sqrt{77}} \cdot- 5 \sqrt{21} = \\ = -60- 30 \sqrt{21} + 90 \sqrt{77} + 315 \sqrt{33} $$ |
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