Answer
$$(3-\sqrt{7})\cdot(-10-\sqrt{21})=-30-3\sqrt{21}+10\sqrt{7}+7\sqrt{3}$$
Explanation
| $$ \begin{aligned}(3-\sqrt{7})\cdot(-10-\sqrt{21})& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-30-3\sqrt{21}+10\sqrt{7}+7\sqrt{3}\end{aligned} $$ | |
| ① | $$ \color{blue}{ \left( 3- \sqrt{7}\right) } \cdot \left( -10- \sqrt{21}\right) = \color{blue}{3} \cdot-10+\color{blue}{3} \cdot- \sqrt{21}\color{blue}{- \sqrt{7}} \cdot-10\color{blue}{- \sqrt{7}} \cdot- \sqrt{21} = \\ = -30- 3 \sqrt{21} + 10 \sqrt{7} + 7 \sqrt{3} $$ |
This page was created using
Simplify Radical Expression