Answer
$$(-7-\sqrt{2})\cdot(3+\sqrt{5})=-21-7\sqrt{5}-3\sqrt{2}-\sqrt{10}$$
Explanation
| $$ \begin{aligned}(-7-\sqrt{2})\cdot(3+\sqrt{5})& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-21-7\sqrt{5}-3\sqrt{2}-\sqrt{10}\end{aligned} $$ | |
| ① | $$ \color{blue}{ \left( -7- \sqrt{2}\right) } \cdot \left( 3 + \sqrt{5}\right) = \color{blue}{-7} \cdot3\color{blue}{-7} \cdot \sqrt{5}\color{blue}{- \sqrt{2}} \cdot3\color{blue}{- \sqrt{2}} \cdot \sqrt{5} = \\ = -21- 7 \sqrt{5}- 3 \sqrt{2}- \sqrt{10} $$ |
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