Question
Answer
$$(-2-\sqrt{3})\cdot(9-6\sqrt{5})=-18+12\sqrt{5}-9\sqrt{3}+6\sqrt{15}$$
Explanation
| $$ \begin{aligned}(-2-\sqrt{3})\cdot(9-6\sqrt{5})& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-18+12\sqrt{5}-9\sqrt{3}+6\sqrt{15}\end{aligned} $$ | |
| ① | $$ \color{blue}{ \left( -2- \sqrt{3}\right) } \cdot \left( 9- 6 \sqrt{5}\right) = \color{blue}{-2} \cdot9\color{blue}{-2} \cdot- 6 \sqrt{5}\color{blue}{- \sqrt{3}} \cdot9\color{blue}{- \sqrt{3}} \cdot- 6 \sqrt{5} = \\ = -18 + 12 \sqrt{5}- 9 \sqrt{3} + 6 \sqrt{15} $$ |
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