Answer
$$\frac{-16+\sqrt{396}}{2}=-8+3\sqrt{11}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}\frac{-16+\sqrt{396}}{2}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{-16+6\sqrt{11}}{2} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{-8+3\sqrt{11}}{1} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}-8+3\sqrt{11}\end{aligned} $$ | |
| ① | $$ \sqrt{396} =
\sqrt{ 6 ^2 \cdot 11 } =
\sqrt{ 6 ^2 } \, \sqrt{ 11 } =
6 \sqrt{ 11 }$$ |
| ② | Divide both numerator and denominator by 2. |
| ③ | Remove 1 from denominator. |
This page was created using
Simplify Radical Expression