$$ \begin{aligned} x-5(x+3) &= 17&& \text{simplify left side} \\[1 em]x-(5x+15) &= 17&& \\[1 em]x-5x-15 &= 17&& \\[1 em]-4x-15 &= 17&& \text{ move -15 to the right } \\[1 em]-4x &= 17+15&& \\[1 em]-4x &= 32&& \text{ divide both sides by $ -4 $ } \\[1 em]x &= -\frac{32}{4}&& \\[1 em]x &= -8&& \\[1 em] \end{aligned} $$
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