$$x-3 \cdot \frac{x^1}{2}-4 = 0$$

$$ \begin{aligned} x-3 \cdot \frac{x^1}{2}-4 &= 0&& \text{multiply ALL terms by } \color{blue}{ 2 }. \\[1 em]2x-2\cdot3 \cdot \frac{x^1}{2}-2\cdot4 &= 2\cdot0&& \text{cancel out the denominators} \\[1 em]2x-3x-8 &= 0&& \text{simplify left side} \\[1 em]-x-8 &= 0&& \text{ move the constants to the right } \\[1 em]-x &= 8&& \text{switch signs on both sides} \\[1 em]x &= -8&& \\[1 em] \end{aligned} $$

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