$$ \begin{aligned} x+5 &= \frac{x}{3}&& \text{multiply ALL terms by } \color{blue}{ 3 }. \\[1 em]3x+3\cdot5 &= 3 \cdot \frac{x}{3}&& \text{cancel out the denominators} \\[1 em]3x+15 &= x&& \text{move the $ \color{blue}{ x } $ to the left side and $ \color{blue}{ 15 }$ to the right} \\[1 em]3x-x &= -15&& \text{simplify left side} \\[1 em]2x &= -15&& \text{ divide both sides by $ 2 $ } \\[1 em]x &= -\frac{15}{2}&& \\[1 em] \end{aligned} $$
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