$$x^2+2x-5 = 31$$
Answer
$$ \begin{matrix}x_1 = -1-\sqrt{ 37 } & x_2 = -1+\sqrt{ 37 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} x^2+2x-5 &= 31&& \text{move all terms to the left hand side } \\[1 em]x^2+2x-5-31 &= 0&& \text{simplify left side} \\[1 em]x^2+2x-36 &= 0&& \\[1 em] \end{aligned} $$
$ x^{2}+2x-36 = 0 $ is a quadratic equation.
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