$x^{2} + \frac{x ^{1}}{2} = 18$

Answer

$x_{1} = 4 x_{2} = - \frac{9}{2}$

Explanation

x^{2} + \frac{x ^{1}}{2} 2 x^{2} + 2 \cdot \frac{x ^{1}}{2} 2 x^{2} + x 2 x^{2} + x - 36 = 18 = 2 \cdot 18 = 36 = 0 multiply ALL terms by 2 . cancel out the denominators move all terms to the left hand side

$2 x^{2} + x - 36 = 0$ is a quadratic equation.

You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this equation.

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x2+2x1​=18

x1​=4​x2​=−29​​

$x^{2} + \frac{x ^{1}}{2} = 18$

$x_{1} = 4 x_{2} = - \frac{9}{2}$