$$x^2-3x = 0$$
Answer
$$ \begin{matrix}x_1 = 0 & x_2 = 3 \\[1 em] \end{matrix} $$
Explanation
In order to solve $ \color{blue}{ x^{2}-3x = 0 } $, first we need to factor our $ x $.
$$ x^{2}-3x = x \left( x-3 \right) $$$ x = 0 $ is a root of multiplicity $ 1 $.
The second root can be found by solving equation $ x-3 = 0$.
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