$$\frac{x^2}{4} = x$$
Answer
$$ \begin{matrix}x_1 = 0 & x_2 = 4 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} \frac{x^2}{4} &= x&& \text{multiply ALL terms by } \color{blue}{ 4 }. \\[1 em]4 \cdot \frac{x^2}{4} &= 4x&& \text{cancel out the denominators} \\[1 em]x^2 &= 4x&& \text{move all terms to the left hand side } \\[1 em]x^2-4x &= 0&& \\[1 em] \end{aligned} $$
In order to solve $ \color{blue}{ x^{2}-4x = 0 } $, first we need to factor our $ x $.
$$ x^{2}-4x = x \left( x-4 \right) $$$ x = 0 $ is a root of multiplicity $ 1 $.
The second root can be found by solving equation $ x-4 = 0$.
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