$$\frac{\frac{\frac{x}{x+3}}{x}}{x-4} = 0$$

$$ \begin{aligned} \frac{\frac{\frac{x}{x+3}}{x}}{x-4} &= 0&& \text{multiply ALL terms by } \color{blue}{ (x-4)x(x+3) }. \\[1 em](x-4)x(x+3)\frac{\frac{\frac{x}{x+3}}{x}}{x-4} &= (x-4)x(x+3)\cdot0&& \text{cancel out the denominators} \\[1 em]x &= 0&& \text{ divide both sides by $ 1 $ } \\[1 em]x &= \frac{0}{1}&& \\[1 em]x &= 0&& \\[1 em] \end{aligned} $$

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