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$$s^2(s+36) = 0$$
Answer
$$ \begin{matrix}s_1 = 0 & s_2 = -36 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} s^2(s+36) &= 0&& \text{simplify left side} \\[1 em]s^3+36s^2 &= 0&& \\[1 em] \end{aligned} $$
In order to solve $ \color{blue}{ x^{3}+36x^{2} = 0 } $, first we need to factor our $ x^2 $.
$$ x^{3}+36x^{2} = x^2 \left( x+36 \right) $$
$ x = 0 $ is a root of multiplicity $ 2 $.
The second root can be found by solving equation $ x+36 = 0$.
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